1173. 即时食物配送 I

题目

配送表: Delivery

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+-----------------------------+---------+
| Column Name | Type |
+-----------------------------+---------+
| delivery_id | int |
| customer_id | int |
| order_date | date |
| customer_pref_delivery_date | date |
+-----------------------------+---------+
delivery_id 是表的主键。
该表保存着顾客的食物配送信息,顾客在某个日期下了订单,并指定了一个期望的配送日期(和下单日期相同或者在那之后)。

如果顾客期望的配送日期和下单日期相同,则该订单称为 「即时订单」,否则称为「计划订单」。

写一条 SQL 查询语句获取即时订单所占的比例, 保留两位小数。

查询结果如下所示:

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Delivery 表:
+-------------+-------------+------------+-----------------------------+
| delivery_id | customer_id | order_date | customer_pref_delivery_date |
+-------------+-------------+------------+-----------------------------+
| 1 | 1 | 2019-08-01 | 2019-08-02 |
| 2 | 5 | 2019-08-02 | 2019-08-02 |
| 3 | 1 | 2019-08-11 | 2019-08-11 |
| 4 | 3 | 2019-08-24 | 2019-08-26 |
| 5 | 4 | 2019-08-21 | 2019-08-22 |
| 6 | 2 | 2019-08-11 | 2019-08-13 |
+-------------+-------------+------------+-----------------------------+

Result 表:
+----------------------+
| immediate_percentage |
+----------------------+
| 33.33 |
+----------------------+
2 和 3 号订单为即时订单,其他的为计划订单。

解法

解法一:

嵌套

SQL

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select round(
(select count(*) from Delivery where order_date=customer_pref_delivery_date) /
(select count(*) from Delivery),4
)*100 as immediate_percentage

解法二:

官方题解

SQL

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select 
round(
(select count(*) from Delivery where order_date=customer_pref_delivery_date) /
(select count(*) from Delivery), 4
) * 100
as immediate_percentage

解法三:

条件选择

SQL

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select round(
sum(case when order_date=customer_pref_delivery_date then 1 else 0 end) /
count(*)
,4)*100
as immediate_percentage
from Delivery

解法四:

逻辑真值

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select round(
sum(order_date=customer_pref_delivery_date) /
count(*)
,4)*100
as immediate_percentage
from Delivery

参考资料

LeetCode-1173. 即时食物配送 I(简单)

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